Physics Problems

1. For the concave mirror shown below, the focal point is + 10 cm. Calculate the image distance, calculate the magnification, and draw a ray diagram for an object located:

a) at 4 times the focal length , b) at 1.5 times focal length, c) at one half the focal length

(13.33 cm, -1/3; 30 cm, -2; -10 cm, +2)

2. For the convex mirror shown below, the focal point is -10 cm. Calculate the image distance, calculate the magnification, and draw a ray diagram for an object located:

a) at 4 times the focal length, b) at 1.5 times focal length, c) at one half the focal length

(-8 cm, +1/5; - 6 cm, +2/5; -3.33 cm, +2/3)

3. A converging thin lens with a focal point of 12 cm. is shown below. Determine the image location and the magnification from an object located: a) 30 cm; b) 18 cm; c) 6 cm. from the lens. Draw the ray diagrams for each case. (20 cm, -2/3, 36 cm, -2, -12 cm, +2)

4. A diverging thin lens with a focal point of -12 cm. is shown below. Determine the image location and the magnification from an object located: a) 30 cm; b) 18 cm; c) 6 cm. from the lens. Draw the ray diagrams for each case. (-8.57 cm, +2/7, -7.2 cm, +2/5, -4 cm, +2/3)

5. A converging and diverging thin lens combination is shown below. There is a focal length of 10 cm for the converging lens and -12 cm for the diverging lens. The lenses are separated by a distance of 24 cm. An object is located 12 cm in front of the coverging lens. Determine the final image location and the magnification. Draw the ray diagram. (–18 cm from lens 2, +2.5 total)

6. A diverging and converging thin lens combination is shown below. There is a focal length of -10 cm for the diverging lens and 10 cm for the converging lens. The lenses are separated by a distance of 24 cm. An object is located 12 cm in front of the diverging lens. Determine the final image location and the magnification. Draw the ray diagram. (15 cm from lens 2, -.227 total)